-0.1x^2+4x-30=80

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Solution for -0.1x^2+4x-30=80 equation: 



-0.1x^2+4x-30=80

We move all terms to the left:

-0.1x^2+4x-30-(80)=0

We add all the numbers together, and all the variables

-0.1x^2+4x-110=0

a = -0.1; b = 4; c = -110;
Δ = b2-4ac
Δ = 42-4·(-0.1)·(-110)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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